编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。 不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。 示例 1: 输入:["h","e","l","l","o"] 输出:["o","l","l","e","h"] 示例 2: 输入:["H","a","n","n","a","h"] 输出:["h","a","n","n","a","H"]
自己题解:
class Solution { public void reverseString(char[] s) { for (int i=0; i<s.length/2; i++) { char t = s[i]; s[i] = s[s.length-i-1]; s[s.length-i-1] = t; } } }
分析:
1.很easy的一道题